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it takes a rat 65 seconds to run from its food source to its home. If the rat has to run 28 meters which is going faster: the rat, or a child on a bike moving at 2 m/s?

User Gngrwzrd
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Given data:

The given distance covered by rat is d= 28 m.

The given time is t= 65 seconds.

The speed of the child is s'=2 m/s.

The expression for the speed is,


\begin{gathered} s=(28)/(65)\text{ m/s} \\ =0.43\text{ m/s} \end{gathered}

As the speed of the child is greater than speed of the rat, so child is going faste.

r

User Teastburn
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