Question

The formula k=5/9(f-32)+273.15 converts temperature of the object in a laboratory is cooled to 1.5 kelvin. What is the temperature of the object in degrees fahrenheit?

Answer 1

`\begin{gathered} k=(5)/(9)(f-32)+273.15 \\ k=1.5 \\ 1.5=(5)/(9)(f-32)+273.15 \\ \text{Subtract 273.15 from both sides} \\ 1.5-273.15=(5)/(9)f-(160)/(9)\Rightarrow(5)/(9)f=1.5-273.15+(160)/(9) \\ (5)/(9)f=-253.872 \\ MultiplyBothSideBy,(9)/(5) \\ f=(9)/(5)\cdot(-253.872) \\ f=-456.97^(\circ) \end{gathered}`

The temperature of the object is -456.97 degrees