Question

1)Find the probability of randomly selecting the correct access code on the first try 4 digits (0 through 9)2)find the probability of NOT selecting the correct access code on the first try

Answer 1

There are 10 digits from 0 to 9.

First digit 10 ways

Second digit 10 ways

Third digit 10 ways

Fourth digit 10 ways

`\text{There are 10}*10*10*10\text{ ways for four digits.}`

`\text{There are 10}000\text{ ways for four digits.}`

Hence the total outcomes =10000

Selecting the correct access code on the first try given favorable outcomes =1.

`\text{The probability of randomly selecting the correct access code on the first try=}\frac{favorable\text{ outcome}}{\text{Total outcomes}}`

`\text{=}(1)/(10000)`

`=0.0001`

Hence the probability of randomly selecting the correct access code on the first try is 0.0001.

The probability of not selecting the correct access code on the first try=1-The probability of selecting the correct access code on the first try

The probability of not selecting the correct access code on the first try=1-0.0001

Hence the probability of not selecting the correct access code on the first try=0.9999.