Question

How many ounces of a 5% alcohol solution must be mixed with 17 ounces of a 10% alcohol solution to make a 6% alcohol solution?

Answer 1

Let x be number or ounces of a 5% alcohol solution, then:

`x(0.05)+17(0.10)=(x+17)(0.06)`

Solving the above equation for x, we get:

`\begin{gathered} 0.05x+1.7=0.06x+1.02 \\ 0.01x=1.7-1.02 \\ 0.01x=0.68 \\ x=68 \end{gathered}`

Therefore, you must add 68 ounces of the 5% alcohol solution.