Question

What is the image distance if a 5.00 cm tall object is placed 2.33 cm from a converging lens with a focal length of 5.75 cm?0.603cm1.66cm-0.255cm-3.92cm

Answer 1

We will have the following:

First, we will recall that:

`(1)/(f)=(1)/(v)+(1)/(u)`

That is:

`\begin{gathered} (1)/(5.75)=(1)/(2.33)+(1)/(u)\Rightarrow(1)/(u)=-(1368)/(5359) \\ \\ \Rightarrow u=-(5359)/(1368)\Rightarrow u\approx-3.92 \end{gathered}`

So, the image distance is approximately -3.92 cm.