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The volume of ammonia gas at .930 atm of pressure is gradually decreased from 96.2mL to 44.7mL. What is the final pressure of ammonia if there is no change in temperature?

User Zorzi
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1 Answer

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Initial Pressure = P₁ = 0.930 atm

Final Pressure = P = ?

Initial Volume = V₁= 96.2 mL

Final Volume = V = 44.7 mL

Temperature = constant

If we consider that ammonia as an Ideal Gas, and since the temperature is constant we can apply Boyle's Law. It says that at constant temperature:

P * V = P₂ * V₂

If we divide at both sides by V₂:

P₁* V₁ / V₂ = P₂ * V₂ / V₂

On the right side we can cancel V₂ and we get:

P₁* V₁ / V₂ = P₂

P₂ = P₁* V₁ / V₂

Replacing by the values that we were given:

P2 = 0.930 atm * 96.2 mL / (44.7 mL)

P2 = 2.00 atm

So the final pressure is 2.00 atm

User TestTester
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