Explanation:
emergency ? why ? you are in the middle of a game with such an unfair die ?
the probabilty for a number of a regular die is 1/6 (desired cases divided by total possible cases).
the probability to role an even number is therefore 3/6 = 1/2.
that means, even and odd are the 2 possible outcomes.
now, for the unfair die we can see it as if we have now 4 possible outcomes : 3 times an even number, and 1 time an odd number.
so, the probability to roll an even number is 3/4 (and for an odd number 1/4).
now, we roll it twice.
for the sum to be even, we either have to roll 2 even numbers or 2 uneven numbers.
the probabilty is the sum of the both probabilities (it is an exclusive "or" relationship).
the probability to roll 2 even numbers is
3/4 × 3/4 = 9/16
the probability to roll 2 uneven numbers is
1/4 × 1/4 = 1/16
the sum is
9/16 + 1/16 = 10/16 = 5/8
so, E is the right answer.