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Suppose medical records indicate that the length of newborn babies (in inches) is normally distributed with a mean of 20 and a standard deviation of 2.6. Find the probability that a given infant is longer than 20 inches. [? ]%

User Oobgam
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To find the probability we need to use the z score formula, given by:


z=(x-\mu)/(\sigma)

where x is the value we like, mu is the median and sigma is the standard deviation.

Then the z score is:


z=(20-20)/(2.6)=0

Then we have to look for the proability:


P(z>0)=0.5

Therefore the probability that a given infant is longer than 20 inches is 0.5 or 50%.

User ThePedestrian
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