Question

How to find two consecutive whole numbers that square root 40 lies between

Answer 1

First, we need to identify the square root of the fisrt squared numbers:

`\begin{gathered} √(1)=\text{ 1} \\ √(4)=2 \\ √(9)=3 \\ √(16)=4 \\ √(25)=5 \\ √(36)=6 \\ √(49)=7 \\ √(64)=8 \end{gathered}`

Since 40 is a number between 36 and 49, we can say that the square root of 40 is between 6 and 7. So:

`6<\sqrt{40\text{ }}<7`