Question

Find the equaton of the line in point-slope form that passes through (-4,6) and (-2,5)

Answer 1

`\begin{gathered} \text{The equation of a line in point-slope form is} \\ y-y_1=m(x-x_1)_{} \\ \text{where} \\ m=(y_2-y_1)/(x_2-x_1) \end{gathered}`
`\begin{gathered} \text{ In this case, we have that} \\ (x_1,y_1_{})=(-4,6) \\ (x_2,y_2)=(-2,5) \\ \end{gathered}`
`\begin{gathered} \text{ So} \\ m=(5-6)/(-2-(-4)) \\ =(-1)/(2) \\ m=-(1)/(2) \end{gathered}`
`\begin{gathered} \text{ Thus, the equation of the line is} \\ y-6=-(1)/(2)(x+4) \end{gathered}`