Question

A motorcycle has a constant acceleration of 3.74 m/s2. Both the velocity and acceleration of the motorcycle point in the same direction. How much time is required for the motorcycle to change its speed from (a)21.5 to 31.5 m/s, and (b)51.5 to 61.5 m/s?(a)Number ______ Units_________(b)Number ______ Units_________

Answer 1

Since the acceleration is constant we know that it is given by:

`a=(v_f-v_0)/(t)`

from where we have that:

`t=(v_f-v_0)/(a)`

once we have this equation we can determine the time by plugging the values of the acceleration and velocities.

a)

In this case we have that:

`t=(31.5-21.5)/(3.74)=2.67`

Therefore it takes 2.67 s.

b)

In this case we have that:

`t=(61.5-51.5)/(3.74)=2.67`

Therefore it takes 2.67 s.