Question

A quantity of steam (650 g) at 116°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?answer in:____ kcal

Answer 1

Answer:

Total heat removed = 473.04 kCal

Step-by-step explanation:

Heat removed to convert the 116°C to 100°C steam

`\begin{gathered} H=mc(\theta_2-\theta_1) \\ \\ H=650(1.996)(116-100) \\ \\ H=20758.4J \end{gathered}`

Heat removed from 100°C of steam to 100°C of water (Latent heat of condensation)

`\begin{gathered} H_c=650*2257 \\ \\ H_c=1467050J \end{gathered}`

Heat removed from 100°C water to 0°C water

`\begin{gathered} H_w=650*4.2*100 \\ \\ H_w=273000J \end{gathered}`

Heat removed from 0°C water to 0°C ice

`\begin{gathered} H_i=mL_f \\ \\ H_i=650(336) \\ \\ H_i=218400J \end{gathered}`

Total heat removed = 20758.4J + 1467050 + 273000 + 218400

Total heat removed = 1979208.4 J

Convert to kilocalorie

Total heat removed = 1979208.4/4184

Total heat removed = 473.04 kCal