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Find the sum to infinity 16,4,1,1/4

User Shreddd
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Answer:

The sum to infinity of the given series is;


S_(\infty)=21(1)/(3)

Step-by-step explanation:

From the given series, we can see that the series is a Geometric Progression (GP) because it has a common ratio;


\begin{gathered} r=(4)/(16)=(1)/(4) \\ r=0.25 \end{gathered}

The formula to calculate the sum to infinity of a GP is;


\begin{gathered} S_(\infty)=(a)/(1-r) \\ \text{For;} \\ 0Where;<p>a = first term = 16</p><p>r = common ratio = 0.25.</p><p></p><p>substituting we have;</p>[tex]\begin{gathered} S_(\infty)=(16)/(1-0.25)=(16)/(0.75) \\ S_(\infty)=21(1)/(3) \\ S_(\infty)=21.33 \end{gathered}

Therefore, the sum to infinity of the given series is;


S_(\infty)=21(1)/(3)

User Stephen Mallette
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