Question

In a 250 mL sealed container at 150℃, 0.50 mol of both iodine gas I2(g) and bromine gas, Br2(g) are mixed and allowed to react until they form an equilibrium with iodine monobromide gas IBr(g). The equilibrium constant for this reaction is 1.2 x 102. What are the equilibrium concentrations for iodine gas and bromine gas? I2(g) + Br2(g) ↔ 2IBr(g)

Answer 1

answer and explanation

now that we have the x value we can find the equilbrium concentratoins of tehegases

for Iodine

x =0.456

= 0.5-x

= 0.5-0.456

= 0.035mols

concentration = 0.035mols/ 0.250L

= 0.14M

for Bromine

x =0.456

= 0.5-x

= 0.5-0.456

= 0.035mols

concentration = 0.035mols/ 0.250L

= 0.14M

the concentration of the two gases is 0.14M