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Graph the line passing through (-6,1) whose slope is m= -6

Graph the line passing through (-6,1) whose slope is m= -6-example-1

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As given by the question

There are given that the point (-6, 1) and slope (m) is -6.

Now,

To graph, the line, first, finds the equation of the line by using the given point and slope.

Then,

From the formula of point-slope form:


y-y_1=m(x-x_1)

Where,


x_1=-6,y_1=1,\text{ and m=-6}

Then, put all given values into the above formula:

So,


\begin{gathered} y-y_1=m(x-x_1) \\ y-1_{}=-6(x-(-6)_{}) \\ y-1=-6(x+6) \end{gathered}

Then,


\begin{gathered} y-1=-6(x+6) \\ y-1=-6x-36 \\ y-1+1=-6x-36+1 \\ y=-6x-35 \end{gathered}

Then, the graph of the above equation is shown below:

Graph the line passing through (-6,1) whose slope is m= -6-example-1
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