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How do you find the x intercept for -(x-3)^2+12

1 Answer

5 votes

y=mx+b

This is the equation for the line.

Here the given equation is,


-(x-3)^2+12

We can calculate x intercept by substituting 0 for y, as there is no value of y,

the x intercept is none here. The graph is as follows,

How do you find the x intercept for -(x-3)^2+12-example-1
User Tomasz
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