Question

Consider the equation. Y=x^2+1The next step in graphing a parabola is to find points that will determine the shape of the curve. Find the point on the graph of this parabola that has the x-coordinated x= -2

Answer 1

The graph is

`y=x^2+1`

its a upword parabola and vertex of graph is (0,1)

the point on a graph x=-2

`\begin{gathered} y=x^2+1 \\ y=(-2)^2+1 \\ y=4+1 \\ y=5 \end{gathered}`

so graph of function is :

(B)

the coordinate of graph then x=1

`\begin{gathered} y=x^2+1 \\ y=1^2+1 \\ y=2 \end{gathered}`

the value of y is 2 then value of x=1