Question

Use point-slope form to write the equation of a line that passes through the point

(-3, -16) with slope -
1/2

Answer 1

`y= -\frac12 x +\frac{29}2`

Explanation:

Let's start with the point- slope form:

`y-y_0=m(x-x_0)`

and replace the values we have

`y-(-16) = -\frac12 (x-(-3))`

We're almost there, we just need to write it in a better looking form.

`y+16= -\frac12 (x+3)\\y=-\frac12 x - \frac32 + \frac{32}2\\y= -\frac12 x +\frac{29}2`

Answer 2

Explanation:

Point slope form: y - y1 = m(x -x1)

`y - [-16] = (1)/(2)(x - [-3] )\\\\y + 16 = (1)/(2)(x + 3)\\\\\\y + 16 = (1)/(2)x + (3)/(2)\\\\y =(1)/(2)x+(3)/(2)-16\\\\y=(1)/(2)x +(3)/(2)-(32)/(2)\\\\\\y=(1)/(2)x - (29)/(2)`