Sophie
- The formula for continuously compounded interest is given by:
![A=Pe^(rt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/5drqeoscjn6fncl992j2z04p3erm9eojdf.png)
Where:
A is the amount after t years.
P is the principal.
r is the annual interest rate.
Therefore the equation is:
P = $3500
r = 7.05% = 0.0705
![A=3500e^(0.0705t)](https://img.qammunity.org/2023/formulas/mathematics/college/dupkjn21ny0ss8lrcusp5xvanvxvhb5tyo.png)
- Money in Sophie’s account after 3 years:
t = 3
![A=3500e^(0.0705(3))=3500e^(0.2115)=4324.35](https://img.qammunity.org/2023/formulas/mathematics/college/koeo1rv4mmzmjtk4yhk2qebyqkdvvkq0yz.png)
This is $4324.35
- Money in Sophie’s account after 10 years:
t = 10
![A=3500e^(0.0705(10))=3500e^(0.705)=7083.46](https://img.qammunity.org/2023/formulas/mathematics/college/qz3ws7f9m55dmm3a83l08odl2j9ewxa6hj.png)
This is $7083.46
Answer
Describe the type of equation that models Sophie’s situation: exponential growth model.
Create that equation of Sophie’s situation:
![A=3500e^(0.0705t)](https://img.qammunity.org/2023/formulas/mathematics/college/dupkjn21ny0ss8lrcusp5xvanvxvhb5tyo.png)
Money will be in Sophie’s account after 3 years: $4324.35
Money will be in Sophie´s account after 10 years: $7083.46