Question

An oil tanker holds 3.24 • 10^7 gallons of crude oil. The mass of the oil is 2.13 • 10^8 pounds. What is the density of the oil in kilograms per liter?

Answer 1

The density of the oil in kilograms per liter is 0.78775

Step-by-step explanation

Note: 1 gallon = 3.78541 liters

1 pound = 0.453592 kilogram

Given:

The gallons (volume) of crude oil = 3.24 x 10⁷ gallons

The mass of the crude oil = 2.13 x 10⁸ pounds

Conversion:

The volume in liters of 3.24 x 10⁷ gallons of crude oil will be

`\begin{gathered} =3.78541*3.24*10^7 \\ =1.22647*10^8\text{ liters} \end{gathered}`

Also, the mass in kilograms of 2.13 x 10⁸ pounds of crude oil will be

`\begin{gathered} =0.453592*2.13*10^8 \\ =9.6615*10^7\text{ kilograms} \end{gathered}`

Now, we shall use the formula below to calculate the density

`\begin{gathered} \text{Density = }\frac{Mass\text{ in kilograms}}{\text{Volume in liter}} \\ \text{Mass in kilograms = 9.6615 }*10^7 \\ Volume\text{ in liters =}1.22647*10^8 \\ \therefore Density\text{ in kilograms per liter = }\frac{\text{9.6615 }*10^7}{1.22647*10^8}=0.78775^{} \end{gathered}`