Question

The length of a rectangle is 3in longer than its width.If the perimeter of the rectangle is62in , find its length and width.

Answer 1

We will have the following:

`\begin{gathered} p=2(l+w) \\ \\ and \\ \\ l=w+3 \\ w=w \end{gathered}`

So:

`\begin{gathered} p=2(l+w)\Rightarrow p=2(w+3+w) \\ \\ \Rightarrow p=2(2w+3)\Rightarrow p=4w+6 \end{gathered}`

Then we will have that:

`\begin{gathered} 62=4w+6\Rightarrow4w=56 \\ \\ \Rightarrow w=14 \end{gathered}`

So, the width is 14 inches and the length will then be 17 inches.