Given:
![\begin{gathered} x+2y\le6\ldots\text{ (1)} \\ 3x-4y<2\ldots(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/lisdkswb98d1wnfa75klghqivxl6va3g3a.png)
We have to take the value of x as zero and to find the value of y in bothe the equations to plot the graph.
By taking the value of x as zero in the first equation,
![\begin{gathered} 2y\le6 \\ y\le3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/uipcz2fhynoson33vjppi0ae758dev5vbv.png)
By taking the value of y as zero in the first equation,
![x\le6](https://img.qammunity.org/2023/formulas/mathematics/college/18gd0wzc7bkppxgap927uz5wk4h00bznqw.png)
By taking the value of x as zero in the second equation,
![\begin{gathered} -4y<2 \\ -2y<1 \\ y>-(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gnsl9y2jjnm7yrjd1rfwswd44sixq1byu2.png)
By taking the value of y as zero in the second equation,
![\begin{gathered} 3x<2 \\ x<(2)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7c2yu2d2yfz1ncyc2zy2tkewn8hcps8jtm.png)