Question

Adina sets up a taste test of 3 different waters: tap, bottled in glass, and bottled in plastic. She puts these waters in identical cups and has a friend taste them one by one. The friend then tries to identify which water was in each cup. Assume that Adina's friend can't taste any difference and is randomly guessing. What is the probability that Adina's friend correctly identifies each of the 3 cups of water

Answer 1

Given

3 different waters: tap, bottled in glass, and bottled in plastic.

Find

probability that Adina's friend correctly identifies each of the 3 cups of water

Step-by-step explanation

As we have given three different waters : tap , bottled in glass and bottled in plastic.

number of ways in which the person can make guesses about the 3 cups of water =

`\begin{gathered} ^3P_3 \\ (3!)/(0!) \\ 6 \end{gathered}`

number of ways in which person identifies correctly the 3 cups of water = 1

so , probability that Adina's friend correctly identifies each of the 3 cups of water =

`P\text{ = }\frac{number\text{ of ways in which person identifies correctly the 3 cups of water}}{number\text{ of ways in which the person can make guesses about the 3 cups of water }}`

so , P = 1/6

Final Answer

Therefore , the probability that adina's friend correctly identifies each of the cup of water = 1/6