Question

A right triangle is shown in the figure what is the value of x

Answer 1

So,

We could use the pythagorean theorem as follows:

`(3x)^2+x^2=(\sqrt[]{40})^2`

And then solve for x:

`\begin{gathered} 10x^2=40 \\ x^2=(40)/(10) \\ x^2=4 \\ x=2 \end{gathered}`

Therefore, x=2.