Given that Tom invested $4500 in an investment paying 10% compounded quarterly for 3 years.
We have to find the interest for the given time period.
We know that the formula of amount on a principal P, rate r per annum, time t years where interest is compounding quarterly is:
![A=P(1+(r)/(4))^(4t)](https://img.qammunity.org/2023/formulas/mathematics/college/hx95z8cqhcbdsscr7ee0h63rk622cb0tf6.png)
Here, P = 4500, r = 0.1 and t = 3. So,
![\begin{gathered} A=4500(1+(0.1)/(4))^(4(3)) \\ =4500(1+0.025)^(12) \\ =4500(1.025)^(12) \\ =4500(1.3448) \\ =6051.6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7hfzcy1nye9a3nccmmiut1y8o204h4fx1g.png)
So, the amount we get is $6051.6.
Now, it is known that the interest is the difference between the amount and the principal. So,
![\begin{gathered} \text{ interest}=\text{ amount-principal} \\ =6051.6-4500 \\ =1551.6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fxsp0cw58s90igi3swn0ojviqx8qnrls1u.png)
Thus, the interest is $1551.6.