Question

plant A produced 3 times as many panels as plant b. two percent of the panels from plant A and 5% of the panels from plant b were defective. how many panels did plant b produce if the two plants together produced 990 defective panels

Answer 1

let x the number of panels that Plant A produced

y the number of panels that Plant B produced

then, we have

x = 3y

0.02x + 0.05y = 990

and solve the system:

`\begin{gathered} 0.02(3y)+0.05y=990 \\ 0.06y+0.05y=990 \\ 0.11y=990 \\ (0.11y)/(0.11)=(990)/(0.11) \\ y=9000 \end{gathered}`

answer: plant b produced 9000 panels