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Find the length of the legs of a night triangle whose hypotenuse is 25cm and whose area is 84cm use phytagorean theorem.

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Answer:

Step-by-step explanation:

Here, we want to find the length of the legs of the right triangle given the area and the length of the hypotenuse

We have the sketch of the triangle as shown below:

According to Pythagoras' the square of the length of the hypotenuse equals the sum of the squares of the length of the two other sides

Thus, mathematically:


a^2\text{ + b}^2\text{ = 25}^2

Mathematically, we have the area calculated as:


\begin{gathered} A\text{ = }(1)/(2)* b* h \\ \\ 84\text{ = }(1)/(2)* a* b \\ \\ a\text{ = }(168)/(b) \end{gathered}

Now, we have two equations to solve simultaneously

Substitute equation ii into i

We have that as:


Find the length of the legs of a night triangle whose hypotenuse is 25cm and whose-example-1
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