Question

I REALLY NEED HELP WITH FACTORISING AFTER THIS CAN WE PLEASE DO SOME QUESTIONS BASED ON IT

Answer 1

Step 1:

Write the expression

`14x^2\text{ }-\text{ x - 3}`

Step 2:

To factorize the expression, multiply the leading coefficient with the constant term.

`\begin{gathered} \text{Leading coefficent = 14} \\ \text{constant term = -3} \\ =\text{ 14 }*\text{ -3 = -42} \end{gathered}`

Step 4

Choose two numbers whose product is -42 and the sum is -1 (that is the coefficient of x)

`\begin{gathered} \text{The two numbers are: 6 and -7} \\ \text{Then, split -x into -7x and 6x} \\ \text{Therefore} \\ 14x^2-x-3=14x^2\text{ - 7x + 6x }-3 \\ 14x^2\text{ - 7x + 6x - 3} \\ \text{Pair two terms and factor out the co}mmon\text{ factors} \\ 7x(2x\text{ - 1) + 3(2x - 1)} \\ (2x\text{ - 1)(7x + 3)} \end{gathered}`

Final answer

(2x - 1)(7x + 3)