Question

A circular loop of wire with a diameter of 13.478 cm is in the horizontal plane and carries a current of 1.607 A counterclockwise, as viewed from above. What is the magnetic field, in microTeslas, at the center of the loop?

Answer 1

Given:

The number of the loops, n = 1

The diameter of the loop is d = 2r = 13.478 cm

The current in the loop is I = 1.607 A

To find the magnetic field in micro Tesla

Step-by-step explanation:

The magnetic field can be calculated by the formula

`B\text{ =}(n\mu_0I)/(2r)`

Here, the value of the constant is

`\mu_0=\text{ 12.57}*10^(-7)\text{ H/m}`

On substituting the values, the magnetic field will be

`\begin{gathered} B=(1*12.57*10^(-7)*1.607)/(13.478*10^(-2)) \\ =1.499\text{ }*10^(-5)\text{ T} \\ =14.99*10^(-6)\text{ T} \\ =14.99\text{ }\mu T \end{gathered}`

The magnetic field is 14.99 micro Tesla