Given,
The center of the circle is (6, -3).
The coordinates of the point, circle is passing through (6,6).
The general equation of the circle is,

Here, x, y are the coordinates of the point.
h and k are the center of the circle.
r is the radius of the circle.
Substituting the value of h, k , x and y in the equation of circle then,

So, the radius of the circle is 9.
Substituting the value of h, k and r in the general equation of circle.

Hence, the equation of circle is x^2+y^2-12x+6y-36=0