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What is the equation of a line that passes though the pointe (8, -3) and has a slope of 1/4?

1 Answer

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Answer:

y = (1/4)x - 5

Explanation:

We'll look for an equation having the form y=mx+b, where m is the slope and b is the y-intercept, the value of y when x=0.

We are told the slope, m, is (1/4):

y = (1/4)x+ b

We need to find a value of b such that it forces the line to go through point (8,-3). Enter that point in the equation:

y = (1/4)x + b

-3 = (1/4)(8) + b for (8,-3)

-3 = 2 + b

b = -5

The equation is y = (1/4)x - 5

See attached graph.

What is the equation of a line that passes though the pointe (8, -3) and has a slope-example-1
User Aswin Barath
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