1. Divide the first term of the dividend into the first term of the divisor:
![(6x^2)/(2x)=3x](https://img.qammunity.org/2023/formulas/mathematics/college/ncs48761w14abplwfam76kq96k7atgtffa.png)
2. Multiply the result above by the divisor:
![3x(2x+1)=6x^2+3x](https://img.qammunity.org/2023/formulas/mathematics/college/2uauhdfj1iqun33saagy6hi9lsjrot91d2.png)
3. Subtract the result above from the divident to get a new polynomial:
4. Repeat the process with the new polynomial:
![\begin{gathered} -(16x)/(2x)=-8 \\ \\ -8(2x+1)=-16x-8 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/q8nyjas7ar8au48vyk71bx0qx30d9cga4t.png)
Then, the result of the division is:
![(6x^2-13x+5)/(2x+1)=3x-8+(13)/(2x+1)](https://img.qammunity.org/2023/formulas/mathematics/college/1lt6f7vucwmhigrtjxlubm0bnejodljj29.png)