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How tall is a building that casts a 71-ft shadow when the angle of elevation of the sun is 29 degrees.Round to the nearest foot

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Solution

We will draw a diagram to illustrate the information

Using the concept of SOHCAHTOA

We are given adjacent and we want to find opposite


\begin{gathered} tan\theta=(opposite)/(adjacent) \\ tan29=(H)/(71) \\ cross\text{ multiply} \\ H=71tan29 \\ H=39.35594265 \\ H=39ft \end{gathered}

Therefore, the answer is


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How tall is a building that casts a 71-ft shadow when the angle of elevation of the-example-1
User JDpawar
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