123k views
3 votes
Write the equation for a circle with the following informationcenter: (5,-3) radius: 7

1 Answer

5 votes

Step 1: Problem

To determine the equation of a circle with centre (5, -3) and radius 7

Step 2: Substitute the centre value and radius to the equation


\begin{gathered} \text{Equation of a circle} \\ (x-a)^2+(y-b)^2=r^2 \\ \text{centre (5,-3) , radius =7} \\ a=5,\text{ b=-3, r=7} \\ (x-5)^2+(y-(-3))^2=7^2 \end{gathered}

Step 3: Simplify the above equation


\begin{gathered} (x-5)(x-5)\text{ + (y+3)(y+3) = 49} \\ x^2-5x-5x+25+y^2+3y+3y+9=49 \\ x^2-10x+25+y^2+6y+9=49 \\ x^2+y^2-10x+6y=49-25-9 \\ x^2+y^2-10x+6y=15 \\ x^2+y^2-10x+6y-15=0 \end{gathered}

Hence the equation of the circle is


x^2+y^2-10x+6y-15=0

User CoolUserName
by
9.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories