Question

Solve for x. then find the missing piece(s) of the parallelogram for #7

Answer 1

`\begin{gathered} 2x+30+2x-10=180 \\ 2x+2x+30-10=180 \\ 4x+20=180 \\ 4x=160 \\ x=(160)/(4) \\ x=40^0 \end{gathered}`

Let us find the angles of the parallelogram below

`\begin{gathered} 2x+30 \\ x=40 \\ 2(40)+30 \\ 80+30 \\ 110^0 \end{gathered}`
`\begin{gathered} 2x-10 \\ 2(40)-10 \\ 80-10 \\ 70^0 \end{gathered}`

Theorem+: opposite angles of a parallelogram are the same

Hence the angles of the parallelogram are 110, 70, 110, and 70