To answer this question we will use the z-score.
Recall that the z-score is given as follows:
![\begin{gathered} z=(x-\mu)/(\sigma), \\ \text{where x is the observed value, }\mu\text{ is the mean, and }\sigma\text{ is the standard deviation.} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/42qwk10anjsnozqwa1tzjozlhszn7488ob.png)
The z-score of 54 is:
![z=(54-50)/(5)=(4)/(5)=0.8.](https://img.qammunity.org/2023/formulas/mathematics/college/p877o1h4e2n51856ertkte910hhvoc4bkb.png)
The z-score of 56 is:
![z=(56-50)/(4)=(6)/(5)=1.2.](https://img.qammunity.org/2023/formulas/mathematics/college/9ggkwvjoucv6kipzlehht866j8q8iyj9nc.png)
Now, the probability of flipping 54, 55, or 56 heads is the same as the following probability:
![P(0.8Now, recall, that:[tex]P(aNow, from the given table we get that:[tex]\begin{gathered} P(0.8)=0.7881, \\ P(1.2)=0.8849. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/q3a69aibwzolxwz4a49w0an2vwaq8z0olb.png)
Therefore:
[tex]\begin{gathered} P(0.8
Answer: 0.10.