SOLUTION
Let the total number of cards in Ketin's card collection be k
Let the number of baseball cards be b, and
the number of football cards be f
Now, the ratio of baseball cards to football cards is 6 to 7, that is
![\begin{gathered} b\colon f=6\colon7 \\ (b)/(f)=(6)/(7) \\ \text{cross multiplying, we have } \\ 7* b=6* f \\ 7b=6f \\ \text{dividing both sides by 7 to get b, we have } \\ (7b)/(7)=(6f)/(7) \\ b=(6f)/(7) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1g3q3e1vwrsn37axxrfy2nhx3plf3i2755.png)
Also, he has 120 baseball cards.
This means
![\begin{gathered} b=120 \\ \text{but } \\ b=(6f)/(7) \\ \text{That means that } \\ b=(6f)/(7)=120 \\ So,\text{ } \\ (6f)/(7)=120 \\ (6f)/(7)=(120)/(1) \\ \text{cross multiplying, we have } \\ 6f=120*7 \\ \text{dividing by 6, we have } \\ f=(120*7)/(6) \\ 120\text{ divided by 6 = 20, we have } \\ f=20*7 \\ f=140 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ixclr2nktvfs3cblrep8nlgjvs6fei6imr.png)
So, the total number of cards in Ketin's card collection is
![120+140=260](https://img.qammunity.org/2023/formulas/mathematics/college/eon9dhp509o6mae8bll8owck37kp2irf7m.png)
Hence the answer is 260