Question

Please help me ill mark u as brilliant

Answer 1

see explanation

Explanation:

Given

cotθ =
`(4)/(5)` =
`(adjacent)/(opposite)`

Use Pythagoras' identity to calculate the hypotenuse h

h² = 4² + 5² = 16 + 25 = 41 ( take square root of both sides )

h =
`√(41)`

θ is in quadrant III where sinθ < 0 and secθ < 0

sinθ =
`(opposite)/(hypotenuse)` = -
`(5)/(√(41) )` = -
`(5√(41) )/(41)`

cosθ =
`(adjacent)/(hypotenuse)` = -
`(4)/(√(41) )`

secθ =
`(1)/(cos0)` = -
`(√(41) )/(4)`