In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
sample proportion = 0.3
widest 95% confidence interval
sample = ?
Step 02:
p = 0.3
1 - α = 0.95 =>> z α/2 = 1.96
We must check each value to find the solution.
A. sample = 36
![\begin{gathered} 0.3-1.96\cdot\sqrt[]{(0.3\cdot0.7)/(36)}=0.3-0.1499 \\ 0.3+1.96\cdot\sqrt[]{(0.3\cdot0.7)/(36)}=0.3+0.1499 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7xuhbv11efblmpvik3ftruyig6ed1g04j0.png)
confidence interval (0.1501 , 0.4499)
difference = 0.2998
B. sample = 56
![\begin{gathered} 0.3-1.96\cdot\sqrt[]{(0.3\cdot0.7)/(56)}=0.3\text{ - }0.120 \\ 0.3+1.96\cdot\sqrt[]{(0.3\cdot0.7)/(56)}=\text{ 0.3 + }0.120 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fe37zbzu1xviq3x3ml69polu670a6gsjjy.png)
confidence interval (0.18 , 0.42)
difference = 0.24
Analyzing these two values, we can conclude that the widest confidence interval will be for the smallest sample.
The answer is:
Sample = 36