part 1 of the question is asking us to evaluate expressions to the power of 2. To do that let's remember the following:
![a^2=a* a](https://img.qammunity.org/2023/formulas/mathematics/high-school/8thaymkudedem9aov4ewhbyw22g7ta2qap.png)
Ther is, when a number is elevated to second power it means we have to multiply that number by itself. For example:
![\begin{gathered} 1^2=1*1=1 \\ 2^2=2*2=4 \\ 3^2=3*3=9 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/a5p06pd41urt1tkj33kg86j5957eu76pgl.png)
In the second part of this question, we are asked to evaluate the square root of a number. Let's remember that the square root is the inverse operation of elevating a number to the second power. That is if we have:
![\sqrt[]{a}=b](https://img.qammunity.org/2023/formulas/mathematics/high-school/19wkva949qgfd86cvotkgp2z6x0j07xp05.png)
it means:
![b^2=b* b=a](https://img.qammunity.org/2023/formulas/mathematics/high-school/o6uyz9z49p5jylgkejukta9oaeb9vkmzd4.png)
For example:
![\begin{gathered} \sqrt[]{1}=1 \\ \sqrt[]{4}=2 \\ \sqrt[]{9}=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2awqjyb5xq1ne1janqd3hegkeimal7qp2k.png)
The third part of the questions asks us to solve for "x" the following equation:
![x^2=9](https://img.qammunity.org/2023/formulas/mathematics/high-school/bp388dahzdxeqtk03vkoo6wdp1mgi5990n.png)
To do that we take square root on both sides:
![\sqrt[]{x^2}=\sqrt[]{9}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6osf19sm0efv9g4rp2ejkswuazf7vtho72.png)
Since the square root of a number to the second power is the same number and the square root of 9 is 3, we get:
![x=3](https://img.qammunity.org/2023/formulas/mathematics/high-school/tu78xmfzid4zbk5fl1tm8vw66ibi0yce1h.png)