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Answer:

The fourth choice: y+3 = 1(x+2); y= x-1

Step-by-step explanation:

The point slope form of a linear equation is


y-y_0=m(x-x_0)

where (x0,y0) is a point on the line and m is the slope.

Now we first calculate the slope.


m=(3-(-3))/(4-(-2))=(6)/(6)=1

therefore, we have


y-y_0=1(x-x_0)

Now we use (x0, y0) = (-2, -3) and get


y-(-3)_{}=1(x-(-2))
\boxed{y+3=1\mleft(x+2\mright)}

which is our equation in point-slope form.

Now, we convert the equation above into the slope-intercept form.

Subtracting 3 from both sides gives


y+3-3=x+2-3
\boxed{y=x-1}

which is the equation in slope-intercept form.

Hence, the answer to the question is


y+3=1(x+2);y=x-1

which is the fourth option.

User Paul Freez
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