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5. Prove triangle ABD is congruent to triangle CDB. DC|AB D

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\begin{gathered} \text{The hypotaneous is common for both the triangle} \\ \text{Them angle}\angle A\text{ and }\angle C\text{ both are }\Rightarrow90^(\circ) \\ \text{The length of DC and AB are same.} \\ \text{Thus triangle ADB and triangle CDB both are congruent.} \end{gathered}

User Ramakrishna Guttha
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