Question

The sum of three consecutive integers is 219. find The largest of the three integers.

Answer 1

Let n be the lesser number of the three. Therefore,

`n+(n+1)+(n+2)=219`

Solving for n,

`\begin{gathered} \Rightarrow3n+3=219 \\ \Rightarrow3n=216 \\ \Rightarrow n=72 \end{gathered}`

Then, the three numbers are 72, 73, and 74. The answer is 74