Question

Hi can you help me with this i forgot how to do this

Answer 1

x=−3+√14 or x=−3−√14

Answer 2

Answer: Bottom of explanation

Explanation:

We need to get zero on one side so we can perform the quadratic formula on these. When we make the equation 0=x^2+6x-5, a=1, b=6, and c=-5. With our newfound knowledge, we can perform the quadratic formula,

-b+/-√b^2-4ac/2a

plugging in these numbers, we get two solutions through:

`(-6+√(36^2-4(1*-5)))/(2*1)`

`(-6-√(36^2-4(1*-5)))/(2*1)`

Solutions:

`x_(1)=`
`-3+√(329)`

`x_(2)=`
`-3-√(329)`