Question

To beA train started from City A to City B at 13:30. The train travelledat an average speed of 180 miles per hour. If the distancebetween City A and City B is 756 miles, at what time did thetrain arrive at City B? Give your answer in a 24-hour clockformat, such as 19:00. DEnter the answer

Answer 1

Remember that

the speed is equal to divide the distance by the time

speed=d/t

solve for t

t=d/speed

we have

d=756 miles

speed=180 miles per hour

substitute

t=756/180

t=4.2 hours

4.2 hours=4 hours +0.20 hours

Convert 0.20 hours to minutes

Multiply by 60

0.20 h=0.20*60=12 minutes

so

4.2 hours=4 h 12 min

therefore

A train started from City A to City B at 13:30.

13:30+ 4h 12 min=17:42 hrs