Question

Calculate the answers. 13. An orbiting satellite is positioned 3,105 mi above the earth (rearth = 3,959 mi) and orbits the earth once every 201.3 min. Assuming its orbit is a circle, find the distance traveled in 50.0 min.

Answer 1

first you will calculate the speed of the orbiting satelite

`\text{speed = }(dis\tan ce)/(time)`

distance = circumference of the of the orbit

`\begin{gathered} \text{circumference = 2}*\pi*\text{ r} \\ r\text{ = radius of the earth + the height of the satelite above the earth} \\ r\text{ = 3105+3959 =7064mi} \end{gathered}`
`\text{circ of the orbit = }2\text{ }*3.142*7064=\text{ 44390.176}`
`\text{speed = }(44390.176)/(201.3)\text{ = 220.52mi/min}`

distance covered in 50.0 min

distance = speed X time

`\text{distance = 220.52}*50=11026mi`

the distance traveled is 11026 mi