Answer : x = 30 degrees
< JKL and < MKQ are complementary
Let < MKQ = x
Angle JKL is twice the measure of angle MKQ
JKL = 2 x MKQ
Sum of a complementary angles = 90 degrees
< JKL + < MKQ = 90
< JKL = 2MKQ
Substitute the value of < jkl
2(<2MKQ + Since, Therefore,
2x + x = 90
3x = 90
Divide both sides by 3
3x / 3 = 90/3
x = 30 degrees