Answer:

Step-by-step explanation:
To properly classify the traingle, we need to get the length of the sides
To get the length of the sides, we need to get the distance between each two points using the distance between two points formula
Mathematically,we have the formula as:
![D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/blvd5bizpfsp1rctvjgv7h5pscu3lv9ga5.png)
Where (x1,y1) refers to the coordiantes of the first point while (x2,y2) refers to the coordinates of the second point
let us get the coordinates of the individual points as seen from the plot shown
C (1,8)
A (5,10)
T (7,6)
So, let us find the distance between each two points
For AC, we have:
![D\text{ = }\sqrt[]{(5-1)^2+(10-8)^2}\text{ = }\sqrt[]{20}](https://img.qammunity.org/2023/formulas/mathematics/college/927u2wwcq0r446cricfkjqecnzmcalkxlw.png)
For AT, we have:
![D=\sqrt[]{(7-5)^2+(6-10)^2\text{ }}\text{ = }\sqrt[]{20}](https://img.qammunity.org/2023/formulas/mathematics/college/omiw5wwg1b4fsby9rq8ayct82psqj14yuu.png)
Lastly, for CT, we have:
![D\text{ = }\sqrt[]{(7-1)^2+(6-8)^2\text{ }}\text{ = }\sqrt[]{40}](https://img.qammunity.org/2023/formulas/mathematics/college/an74rkedevdoef22qbtnzmuis3hr9hmxrw.png)
From our calculations, we can see that AC = AT
If we have a triangle which has two of its sides equal in length (the angle facing these sides would be same too), we call this an isosceles triangle
So, the class of triangle CAT is isosceles triangle