Question

Helpppppppppppppppppppp

Answer 1

2nd option

Explanation:

given a quadratic in standard form

y = ax² + bx + c

• If a > 0 then minimum vertex

• If a < 0 then maximum vertex

Here a = - 1 < 0 then maximum

The maximum value is the value of the y- coordinate of the vertex

The x- coordinate of the vertex is

x = -
`(b)/(2a)`

Here a = - 1 and b = 3 , then

x = -
`(3)/(-2)` =
`(3)/(2)`

Substitute this value into the equation for corresponding y- value

y = - (
`(3)/(2)` )² + 3(
`(3)/(2)` ) - 1 = -
`(9)/(4)` +
`(9)/(2)` - 1 = -
`(9)/(4)` +
`(18)/(4)` -
`(4)/(4)` =
`(5)/(4)`

Then maximum value of
`(5)/(4)`