Question

Question 3 4.5 pts At the honor roll party, students had the choice of cheese or pepperoni pizza and coke or sprite. Of the 125 students that made the honor roll 64% had cheese pizza. There were 48 students that had cheese pizza and a coke. 5 more students chose to have a Coke rather than Sprite. Complete the table below.

Answer 1

The table would look like this;

We are told that Of the 125 students that made the honor roll 64% had cheese pizza.

64% of 125 is 80 students, therefore, 80 students in total had cheese pizza.

Let's fill that in.

We now know that those who had pepperoni pizza are 125 - 80 = 45 in number.

There were 48 students that had cheese pizza and a coke, let's fill that in too, we have.

This means that the number of students that had a cheese and sprite is 80 - 48 = 32 students.

We are also told that 5 more students chose to have a coke than a sprite.

Let the total number that chose coke be x.

Then the total who chose sprite would be x - 5.

But these total must add up to 125.

So;

`\begin{gathered} x+x-5=125 \\ 2x-5=125 \\ 2x=130 \\ x=(130)/(2)=65 \\ x-5\text{ = 60} \end{gathered}`

Therefore, 65 students took coke in total and 60 took sprite, let's fill that in too.

We can now fill in the pepperoni column.

For pepperoni and coke, we subtract 48 from 65 to obtain 17

For pepperoni and sprite, we subtract 32 from 60 to obtain 28

ii. The joint relative frequency of the students who had a sprite and pepperoni pizza.

From the table, the joint relative frequency of those who had a sprite and a pepperoni pizza is

`\begin{gathered} (28)/(45) \\ \end{gathered}`

i.e 28/45 or 0.6 of those who had pepperoni pizza, took sprite.